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Ap chemistry

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how many milliliters of a 0.46 M HCl solution are needed to react completely with a 6.4 g of zinc to form zinc (ii) chloride answer in mL
Help please :( I was absent and don't know where to start

  • Ap chemistry -

    start by reading your text book. I'm sure there's a section regarding moles.

    Zn has a mol wt of 65.39, so 6.4g = 0.1 moles of Zn

    Since the reaction is

    Zn + 2HCl = ZnCl2 + H2
    each mole of Zn reacts with 2 moles HCl

    So, you need .2 moles HCl

    .46M HCl has .46 moles/liter

    So, you need .2/.46 = .434 liters, or 434ml

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