# Precalculas

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The sum of the first 30 terms of one arithmetic sequence is 300 more than the sum of the first 30 terms of another arithmetic sequence. what could the Â sequences be?

• Precalculas -

assume they have the same first term.
Then 29(d2-d1) = 300

29 does not divide 300, but it does divide 290

So, in order for s2=s1+300, a2-a1=10

one solution would be

a1=0 d1=1
a2=10 d2=11

0+29=29
10+29*11 = 329

a1+29d1 + 300 = (a1+10) + 29(d1+10)

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