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if Y varies jointly as X and the square of Z, and if Y=24 when X=2 and Z=6, find Y when X=10 and Z=9

  • math -

    y = kxz^2 , where k is a constan

    given: y = 24, x=2, z=6

    24 = k(2)(36)
    k = 24/72 = 1/3

    y = (1/3)xz^2
    when x=10,z=9
    y = (1/3)(10)(81) = 10/243

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