Hg has an AW of 200.59 g/mol and HgS has a MW of 232.66 g/mol.
Compute the gram of Hg needed to prepare 20 g of standard containing 1% Hg(wt/wt)
Then compute the gram of HgS needed to prepare 20 g of standard containing this same 1% (wt/wt).
nevermind i got the answer (:
No i didn't! Who the heck use my name to answer that post????!!!!
To compute the grams of Hg needed to prepare 20 g of a standard containing 1% Hg (wt/wt), we can use the formula:
Grams of Hg = (Percentage of Hg / 100) * Total weight of standard
Given that the standard contains 1% Hg and the total weight is 20 g, we can substitute these values into the formula:
Grams of Hg = (1 / 100) * 20 = 0.2 g
Therefore, you would need 0.2 grams of Hg to prepare 20 grams of a standard containing 1% Hg (wt/wt).
To compute the grams of HgS needed to prepare 20 g of a standard containing 1% Hg (wt/wt), we need to take into account the molecular weights of Hg and HgS.
First, let's calculate the grams of Hg in 1% (wt/wt) of the standard, which is 0.2 g:
Grams of Hg = 0.2 g
Next, let's calculate the grams of HgS in the standard using the molecular weights:
Grams of HgS = (Grams of Hg / Molecular weight of Hg) * Molecular weight of HgS
Substituting the given values:
Grams of HgS = (0.2 / 200.59) * 232.66
Calculating this expression:
Grams of HgS = 0.116 g
Therefore, you would need approximately 0.116 grams of HgS to prepare 20 grams of a standard containing 1% Hg (wt/wt).
To compute the grams of Hg needed to prepare 20 g of a standard containing 1% Hg (wt/wt), we need to calculate the amount of Hg in 1% of the total weight.
1% Hg (wt/wt) means that in 100 g of the standard, 1 g is Hg.
Now, we need to determine how much Hg is present in 20 g of the standard.
To get the weight of Hg, we need to multiply the weight of the standard (20 g) by the percentage of Hg:
Weight of Hg = 1% * Weight of the standard
Weight of Hg = (1/100) * 20 g
Weight of Hg = 0.01 * 20 g
Weight of Hg = 0.2 g
Therefore, 0.2 grams of Hg is needed to prepare 20 g of the standard containing 1% Hg (wt/wt).
To calculate the grams of HgS needed to prepare 20 g of the standard containing 1% (wt/wt), we need to consider the molar ratio between Hg and HgS.
From the given molecular weights:
- Hg: 200.59 g/mol
- HgS: 232.66 g/mol
To find the amount of HgS needed, we first need to determine the molar mass of Hg in HgS. The molar mass of HgS is equal to the molar mass of Hg plus the molar mass of S (sulfur):
Molar mass of Hg in HgS = Molar mass of HgS - Molar mass of S
Molar mass of Hg in HgS = 232.66 g/mol - Molar mass of S
Now, we can calculate the molar mass of S by subtracting the molar mass of Hg from the molar mass of HgS:
Molar mass of S = Molar mass of HgS - Molar mass of Hg
Molar mass of S = 232.66 g/mol - 200.59 g/mol
Molar mass of S = 32.07 g/mol
Finally, we can calculate the molar mass of Hg in HgS:
Molar mass of Hg in HgS = 232.66 g/mol - 32.07 g/mol
Molar mass of Hg in HgS = 200.59 g/mol
Now, we know the molar mass of Hg in HgS is the same as the molar mass of Hg.
Since the molar mass of Hg is the same as the molar mass of Hg in HgS, we can conclude that the gram of HgS needed to prepare 20 g of the standard is also 0.2 g.