physics
posted by kevin .
In the problem, please assume the freefall acceleration g = 9.80 m/s2 unless a more precise value is given in the problem statement. Ignore air resistance.
A stone is thrown vertically downward from the roof of a building. It passes a window 15.0 m below the roof with a speed of 24.3 m/s. It lands on the ground 4.75 s after it was thrown.
(a) What was the initial velocity of the stone?
(b) How tall is the building?

If building has height H, and stone has initial velocity V,
h(t) = H  15t  4.9t^2
h(4.75) = 0 = H  15(4.75)  4.9*4.75^2
= H  181.81
so, H = 181.81m
H15 = H15t4.9t^2
t = .794
v(t) = V  9.8t
24.3 = V  9.8*0.794
V = 16.52m/s 
thanks for the assistance, but apparently none of the answers are correct according to my homework checker.

h=(v²vₒ²)/2•g,
vₒ= sqrt(v²2•gvh) =
sqrt(24.3²2•9.8•15) = 17.22 m/s.
H=vₒ•t+g•t²/2 =
17.22•4.75+9.8•4.75²/2 =192.35 m