Math
posted by Anonymous .
A ship leaves port at 6 am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15 mph. How far apart, to the nearest tenth of a mile are the 2 ships at 11 pm?

by 11 pm, ship1 has gone 17*12 = 204 miles east
Also, ship2 has gone 180 miles north
the final separation is thus
d^2 = 204^2 + 180^2
d = 272.1 miles
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