Post a New Question

Physics

posted by .

An elevator is moving upward at 0.90 m/s when it experiences an acceleration 0.40 m/s2 downward, over a distance of 0.64 m. What will its final velocity be?

  • Physics -

    .64 = .9 t - .5(.4)t^2
    .2 t^2 - .9 t + .64 = 0
    t = [.9 +/- sqrt (.89 - .512) ]/.4
    t = [ .9 +/- .615 ]/ .4
    we want on the way up so use shorter time
    t = .713 seconds
    v = Vi + a t
    v = .9 - .4 (.713)
    v = .615 m/s

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question