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The shell’s trajectory curves downward because of gravity, so at the time t = 0.217 s
the shell is below the straight line by some
vertical distance ∆h.
Find this distance ∆h in the absence of
air resistance. The acceleration of gravity is
9.8 m/s
Answer in units of m

  • physics -

    ∆h = (g/2)t^2

    Do the numbers

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