Algebra
posted by Frances .
Five times a number decreased by twice the same number.

5N2N

5n  2n =

N+9

the difference of n and 12 is greater than 13

n12
4312=31
31>13
posted by Frances .
Five times a number decreased by twice the same number.
5N2N
5n  2n =
N+9
the difference of n and 12 is greater than 13
n12
4312=31
31>13