pre cal

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(y^2)^-4y^8 simplify

  • pre cal -

    y^2 - 4y^8 = y^2 - (2y^4)^2
    = (y + 2y^4)(y - 2y^4)

    formulas a^2 - b^2 = (a + b)(a - b)

  • pre cal -

    Or, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,

    (y^2)^(-4) * y^8
    = y^(2 * -4) * y^8
    = y^(-8) * y^8
    = y^(-8+8)
    = y^0
    = 1

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