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The equation that has the roots 1, 2, 3 is:
(a) x3 + 6x2 – 11x + 6
(b) x3 – 6x2 + 11x – 6 *
(c) x3 + 6x2 + 11x + 6
(d) x3 – 6x2 – 11x – 6


how ?

  • math -

    if the roots are 1,2,3, then
    (x-1)(x-2)(x-3) = 0
    expand to get (b)

    By the way, none of the answers as written are equations. the correct answer would be

    x^3 - 6x^2 + 11x - 6 = 0

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