Choose a natural number between 1 and 25, inclusive. What is the probability that the number is a multiple of 3?
You have 25 numbers. Only 3, 6, 9, 12, 15, 18, 21 and 24 are multiples of 3.
8/25 = ?
To find the probability of choosing a natural number between 1 and 25 (inclusive) that is a multiple of 3, we first need to determine the total number of natural numbers in this range that are multiples of 3.
To do this, we can consider the pattern of multiples of 3 and observe that the first multiple of 3 in this range is 3 itself, followed by 6, 9, 12, and so on.
So, to find the number of multiples of 3 in the range 1 to 25, we can divide the largest multiple of 3 less than or equal to 25 (which is 24) by 3 and round down to the nearest whole number:
24 รท 3 = 8
Therefore, there are 8 multiples of 3 between 1 and 25.
The total number of integers between 1 and 25 (inclusive) is 25.
To find the probability, we divide the number of favorable outcomes (the number of multiples of 3) by the total number of possible outcomes (total number of integers between 1 and 25):
Probability = number of multiples of 3 / total number of integers between 1 and 25
Probability = 8 / 25
Therefore, the probability of choosing a natural number between 1 and 25 (inclusive) that is a multiple of 3 is 8/25.