College Algebra

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Write the equation of a circle in standard Find the center, radius intercepts and graph the circle. .........x^2+y^2-12x-4y+36=0

  • College Algebra -

    x^2 -12 x = -y^2 + 4 y -36

    x^2 -12 y + 36 = -y^2 + 4 y

    -(x-6)^2 = y^2-4y

    -(x-6)^2 + 4 = y^2 - 4 y + 4
    -(x-6)^2 + 4 = (y-2)^2

    (x-6)^2 + (y-2)^2 = 4

    center at (6,2) radius 2
    you do the rest

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