physics
posted by mitch .
A ball is thrown upward in such a way that its speed is 32.3 m/s when it is at half its maximum height. Find
(a) its maximum height,
(b) its velocity 2.0 s after it's thrown,
(c) its height 2.0 s after it's thrown, and
(d) its acceleration at its maximum height.
Please show work.

(a) v=vₒgt
v=0
t=vₒ/g.
h= vₒtgt²/2=vₒ²/2g =32.3²/2•9.8=53.23 m.
(b) v= vₒ  g•t1 =
= 32.3  9.8•2=12.7 m/s
(c) h= vₒ•t1g•t²/2=
=32.3•2 – 9.8•4/2 =42 m
(d) g=9.8 m/s² (eveywhere)
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