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Math

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How would you simplify the cubed root of 54x^17

??

  • Math -

    (54x^17)^(1/3)
    = (27x^15)^(1/3) (2x^2)^(1/3)
    = 3x^5 (2^(1/3) x^(2/3)

  • Math -

    First I factor 54.
    5 4
    | |
    9 6
    |\ \ \
    3 3 3 2
    {3 3 3} group of threes that can be out of cubed root
    Because there are three threes I take them out of the cubed root (# = im going to consider this as my cubed root button) turning #54x^17 into 3#2x^17

    Now we factor x^17:

    there are 5 groups of 3s in 17 so we would take those out leaving x^2 in the root.

    3#2x^17 turns into 3x^5 # 2x^2
    Then this simplified is therefore

    3x^5 cube root of 2x^2

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