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intermediate algebra

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joe has a collection of nickles and dimes that is worth $3.95. if the number of dimes was doubled and the number of nickles was increased by 21, the value of the coins would be $8.40. How many nickles and dimes does he have? show all your work.
help me please

  • intermediate algebra -

    5n + 10d = 395
    5(n+21) + 10(2d) = 840

    now just solve for n and d:

    34 dimes
    11 nickels

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