# calculus

posted by .

how to find the second derivative of quotient rule?
f(x): 700v^2 + 3450/v
f'(x) : 700v^2 -3450/v^2
f"'(x) : ???

• calculus -

sorry typo error above, question is,

f(x): 700v^2 + 34500/v
f'(x) : 700v^2 -34500/v^2
f"'(x) : ???

• calculus -

the way you typed it ....
f'(x) = 1400v - 3450/v^2 or 1400v - 3450v^-2

f''(x) =1400 + 6900v^-3

IF you meant f(x) = (700v^2 + 3450)/v
I would change it to
f(x) = 700v + 3400v^-1
f'(x) = 700 - 3400v^-2
f''(x) = 6800v^-3 or 6800/v^2

• calculus -

The question should be:

f(x): 700v^2 + 34500/v
f'(x) : 700v^2 -34500/v^2
f''(x) : ???

• calculus -

You missed my point, the issue was not whether it was 3450 or 34500, the point was the use of brackets.

Did you not look at my reply?
simply change 3450 to 34500 and follow the steps.

You derivative would be correct if you had placed it in brackets , such as

f'(x) = (700v^2 - 34500)/v^2

which would reduce to
f'(x) = 700 - 34500/v^2 = 700 - 34500v^-2

then f''(x) = 69000/v^3

• calculus -

pls ignore the above question...

to make it clearer for the question, it is...

f(x): (700v^2 + 34500)/v
f'(x) : (700v^2 -34500)/v^2
f''(x) : ???

• calculus -

i got the answer!! thank you!!!

## Similar Questions

1. ### Calculus

How do I use the chain rule to find the derivative of square root(1-x^2) also, are there any general hints or tips for determining when the chain rule and product or quotient rule should be used?

Find d^2y/dx^2 by implicit differentiation. x^(1/3) + y^(1/3) = 4 I know that first you must find the 1st derivative & for y prime I got 1/3x^(-2/3) + 1/3y^(-2/3) dy/dx = 0 Then for dy/dx I got dy/dx = [-1/3x^(-2/3)] / [1/3y^(-2/3)] …
3. ### calculus

Please help. Applying the chain rule, how do I find the derivative of f(x)=In(e^x-e^-x) (x>0) and then using this answer use the quotient rule to find the second derivative. I cannot do this so any answer greatly appreciated.

Beth earns \$3450 monthly, she is married and claims two exemptions. Find the FIT withheld from her montly check using the percentage method. I have: 2(195.83)= 391.66 3450-391.66 = 3058.34 0.15(3058.34-517) 0.15(2541.34)= \$381 Stacy …
5. ### calculus

Hi i need help in this. Some of the parts i got the answer but some i don't. please help! A ship uses \$(7v^2) of fuel per hour when travelling at a constant speed of v km/h. Other expenses in operating the ship (i.e. crew and equipment) …
6. ### calculus

A ship uses \$( 7v^2 ) of fuel per hour when travelling at a constant speed of v km/h. Other expenses in operating the ship (i.e. crew and equipment) amount to \$345 per hour. The ship makes a journey of 100 km. C(v) : (700v^2 + 34500)/v …
7. ### Applied Calculus

Find the first and second derivative of the function: x/(7x+10) Using quotient rule. This is part of my homework in the section named "Higher Order Derivatives". I am confused on getting the second derivative, as I found the first …
8. ### math

Assuming that a table saw blade has a diameter of 12 inches and spins at 3450 revolutions per minute (RPMs),determine how fast the tip of the teeth of the saw blade are traveling in miles per hour. Answer: 3450/12= 287.5 RPMs 287.5 …
9. ### Calculus

1.) Find the derivative of tan (sec x). 2.) Find the derivative if 1/x in four ways, using the limit process, power rule, quotient rule and implicit differentiation. 3.) Show that the derivative of sec^-1 x is 1/(|x|*sqrt(x^2 -1)). …
10. ### Calculus

Quotient Rule: Use the limit definition of the derivative to prove that the quotient rule

More Similar Questions

Post a New Question