math
posted by karen .
please help!
1.) A random digit from 1 to 9 (inclusive) is chosen, with all digits being equally likely. The probability that when it's squared it will end with the digit 1.
2.) A random number between 1 and 20 (inclusive) is chosen. The probability that its square root will not be an integer.

See response to:
http://www.jiskha.com/display.cgi?id=1344678011
and post if you need more explanations or would like to post your attempt. 
thank you for your help!
can you check if it's correct?
1.) 1/9
2.) 4/2= 1/5 
1.
Note that
21*21=441
49*49=2401
Does that give you a hint?
2.
The question looks for
"The probability that its square root will not be an integer"
so check your answer accordingly. 
Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22
@MathMate