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A volume of 40.0 of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid h2so4. What was the molarity of the solution if 20.02 of 1.50M h2s04 was needed?


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  • chemistry -

    Technically the problem can't be solved because you have no units for 40.0 and 20.02. Assuming those are mL, the problem is solved as follows:

    2KOH + H2SO4 ==> K2SO4 + 2H2O
    mols H2SO4 = M x L = ?
    mols KOH = 2x that (look at the equation coefficients)
    Then M KOH = mols KOH/L KOH.

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