math
posted by dee .
How do you solve this by elimination method? 4x+3y=016x+3=8y

4 x + 3 y = 0
16 x + 3 = 8y
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Multiply the first equation by 4
16 x + 12 y = 0
16 x + 3 = 8y
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Subtract 8 y by second equation
16 x + 12 y = 0
16 x + 3  8 y = 8y  8y = 0
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16 x + 12 y = 0
16 x + 3  8 y = 0
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Subtract 3 by second equation
16 x + 12 y = 0
16 x + 3  8 y  3 = 0  3
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16 x + 12 y = 0
16 x  8 y =  3
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Subtract fsecond equation from first equation
16 x  1 6 x + 12 y  (  8 y ) = 0  (  3 )
12 y + 8 y = 3
20 y = 3 Divide both sides by 20
y = 3 / 20
Put y = 3 / 20 in first equation.
4 x + 3 y = 0
4 x + 3 * 3 / 20 = 0
4 x + 9 / 20 = 0 Subtract 9 / 20 by both sides
4 x + 9 / 20  9 / 20 = 0  9 / 20
4 x =  9 / 20 Divide both sides by 4
x =  9 / ( 20 * 4 )
x =  9 / 80
Solution :
x =  9 / 80 , y = 3 / 20