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How do you solve this by elimination method? 4x+3y=016x+3=8y

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    4 x + 3 y = 0

    16 x + 3 = 8y
    ______________

    Multiply the first equation by 4

    16 x + 12 y = 0

    16 x + 3 = 8y
    ______________

    Subtract 8 y by second equation

    16 x + 12 y = 0

    16 x + 3 - 8 y = 8y - 8y = 0
    ______________

    16 x + 12 y = 0

    16 x + 3 - 8 y = 0
    ______________

    Subtract 3 by second equation

    16 x + 12 y = 0

    16 x + 3 - 8 y - 3 = 0 - 3
    ______________

    16 x + 12 y = 0

    16 x - 8 y = - 3
    ________________

    Subtract fsecond equation from first equation

    16 x - 1 6 x + 12 y - ( - 8 y ) = 0 - ( - 3 )

    12 y + 8 y = 3

    20 y = 3 Divide both sides by 20

    y = 3 / 20

    Put y = 3 / 20 in first equation.

    4 x + 3 y = 0

    4 x + 3 * 3 / 20 = 0

    4 x + 9 / 20 = 0 Subtract 9 / 20 by both sides

    4 x + 9 / 20 - 9 / 20 = 0 - 9 / 20

    4 x = - 9 / 20 Divide both sides by 4

    x = - 9 / ( 20 * 4 )

    x = - 9 / 80


    Solution :

    x = - 9 / 80 , y = 3 / 20

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