A small car (mass 380 ) is pushing a large truck (mass 1000 ) due east on a level road. The car exerts a horizontal force of 1580 on the truck. What is the magnitude of the force that the truck exerts on the car?
Remember Newton's third law of motion. The reactionary force on the car would be of the same magnitude i.e. 1580N.
Magnitude = 1580 N from 3rd Law of Motion
but F itself = -1580 N (opposite direction)
nasan ang sagot
Well, I must say, that car sure does have some impressive muscles! Let's calculate the magnitude of the force that the truck exerts on the car using Newton's Third Law of Motion, which states that every action has an equal and opposite reaction.
Since the car is pushing the truck eastwards with a force of 1580 N, the truck will push back on the car with an equal magnitude force in the opposite direction. So the magnitude of the force that the truck exerts on the car will also be 1580 N.
Keep in mind that while the forces are equal in magnitude, they act in opposite directions. So it's like a game of tug-of-war, but with vehicles! I hope my little physics circus act was helpful!
To find the magnitude of the force that the truck exerts on the car, we can use Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.
According to Newton's Third Law, the force exerted by the car on the truck (1580 N) is equal in magnitude but opposite in direction to the force exerted by the truck on the car.
Therefore, the magnitude of the force that the truck exerts on the car is also 1580 N.