math
posted by Anonymous .
The diagonal of a rectangular room is 52 ft long. one wall measures 28 ft longer than the adjacent wall. Find the dimensions of the room.

x^2 + (x+28)^2 = 52^2
x^2 + x^2 + 56 x + 784 = 2704
2 x^2 + 56 x  1920 = 0
x^2 + 28 x 960 = 0
x = [28 +/ sqrt(28^2 + 3840) ]/2
x = [ 28 +/ 68 ]/2
x = 48
48  28 = 20
so 48 by 20
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