math
posted by donovan .
a security camera needs to be set so that its angle of view includes the area from a doorway to the edge of a parking lot.The doorway is 16m from the camera. The edge of the parking lot is 24m from the camera .The doorway is 28m from the edge of the parking lot. What angle of view is needed for the camera?

Use Law of Cosines:
a = 24 m.
b = 28 m.
c = 16 m.
CosB = (a^2 + c^2  b^2)/2ac
CosB = (576+256784) / 768 = 0.0625
B = 86.4 Deg. = Angle of view.
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