# Algebra

posted by
**Alyonka**
.

The bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 mph faster than the other, what was the speed of each bicyclist?

So far these are the equations I have gotten:

Distance1 + Distance2= 300miles

rate1(time1) + rate2(time2)= 300 miles

rate1= rate2 + 20 mph

time1 + time2 = 6 hrs

However I cant combine them into one equation...

How would you do that