how to solve 20-1/5d=3/10d+16

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To solve the equation 20 - 1/5d = 3/10d + 16, we need to isolate the variable 'd' on one side of the equation. This can be done through a series of algebraic steps:

Step 1: Distribute

Starting with the given equation,
20 - 1/5d = 3/10d + 16

Distribute the 3/10d to both terms on the right side,
20 - 1/5d = (3/10)(d) + 16

Simplify further,
20 - 1/5d = 3/10d + 16

Step 2: Get rid of fractions

To eliminate the fractions, we can multiply all terms by the least common multiple (LCM) of the denominators. In this case, the LCM of 5 and 10 is 10.

Multiply all terms by 10,
10(20) - 10(1/5d) = 10(3/10d) + 10(16)

Simplifying,
200 - 2d = 3d + 160

Step 3: Combine like terms

Combine the like terms on both sides of the equation,
200 - 2d - 3d = 3d + 160 - 3d

Simplifying further,
200 - 5d = 160

Step 4: Isolate the variable

To isolate the variable 'd', we need to move the constant term (160) to the other side of the equation.

Subtract 160 from both sides,
200 - 160 - 5d = 160 - 160

Simplifying,
40 - 5d = 0

Step 5: Solve for 'd'

To solve for 'd', we need to isolate the variable. In this case, we want to move the constant term (40) to the other side of the equation.

Subtract 40 from both sides,
40 - 40 - 5d = 0 - 40

Simplifying,
-5d = -40

Finally, divide both sides by -5 to solve for 'd',
-5d / -5 = -40 / -5

Simplifying further,
d = 8

Therefore, the solution to the equation 20 - 1/5d = 3/10d + 16 is d = 8.

Multiply both sides by 10d.

200d - 2 = 3 + 160d

Subtract 160d and add 2 to both sides.

40d = 5

You should be able to take it from here.