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convert from polar form into rectangular form. type the equation in rectangular form (simplified):

1) rsecθ = 3

2) r=5/cosθ-2sinθ

3) r=5cscθ

  • math -

    we know r^2 = x^2 + y^2 and x/r =cosØ, y/r = sinØ

    given:
    rsecØ = 3
    r = 3/secØ
    r = 3cosØ
    r = 3(x/r)
    r^2 = 3x
    x^2 + y^2 = 3x , rewrite it any way you want.

    the last one is done the same way

    2nd :
    I will assume you r = 5/(cosØ-2sinØ

    r = 5/(x/r - 2y/r)
    r = 5/((x-2y)/r)
    r = 5 * r/(x - 2y)
    1 = 5/(x-2y)
    x-2y = 5

  • math -

    5. Find the Cartesian form of the equation, r3 = 3r cosØ.

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