# math

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convert from polar form into rectangular form. type the equation in rectangular form (simplified):

1) rsecθ = 3

2) r=5/cosθ-2sinθ

3) r=5cscθ

• math -

we know r^2 = x^2 + y^2 and x/r =cosØ, y/r = sinØ

given:
rsecØ = 3
r = 3/secØ
r = 3cosØ
r = 3(x/r)
r^2 = 3x
x^2 + y^2 = 3x , rewrite it any way you want.

the last one is done the same way

2nd :
I will assume you r = 5/(cosØ-2sinØ

r = 5/(x/r - 2y/r)
r = 5/((x-2y)/r)
r = 5 * r/(x - 2y)
1 = 5/(x-2y)
x-2y = 5

• math -

5. Find the Cartesian form of the equation, r3 = 3r cosØ.

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