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If a student desires to produce three times larger and an erect image from a double convex lens with focal length of 15 cm ,then he should place the object from the lens at ;

  • Physica -

    The object has to be placed between the lens and the focus.
    di= distance between the image and the lens;
    do=distance between the object and the lens;
    F =focal length.
    do/di=h/H=1/3 =>
    1/F =1/do-1/di,
    1/F= =
    do=2F/3 =2•0.15/3=0.1 m.

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