physics
posted by zianna .
a projectile is thrown with the speed of 25 meter per seconds in a direction 30° above the horizontal.
how high does it go.
how long does it take to reach the maximum height.
how long does it reach the Projectile along in the air.
how far does it go.

a. Vo = 25 m/s @ 30 Deg.
Xo = 25*cos30 = 21.7 m/s.
Yo = 25*sin30 = 12.5 m/s.
h = (Y^2Yo^2)/2g.
h = (0(12.5)^2) / 19.6=7.97 m.=max ht.
b. Tr = (YYo)/g.
Tr = (012.5) / 9.8 = 1.28 s. =Rise time or time to reach max. ht.
c. Tf = Tr = 1.28 s. = Fall time.
Tr+Tf = 1.28 + 1.28 = 2.56 s. = Time in
air.
d. R = Xo*(Tr+Tf).
R = 21.7 * 2.56 = 55.6 m.
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