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Math-120

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If a force of 5 pounds stretches the spring 2 inches, Find K. How much force is necessary to stretch the spring 14 inches

  • Math-120 -

    K = 5Lbs / 2 In. = 2.5 Lbs/In.

    F = 2.5Lbs/In * 14In. = 35 Lbs.

  • Math-120 -

    and

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