math

posted by .

A batsman hits a cricket ball 'off his toes' towards a fieldsman who is 65 m away. The ball reaches a maximum height of 4.9 m and the horizontal compoenent of its velocity is 28 m/s. Find the constant speed with which the fieldsman must run forward, starting at the instant the ball is hit, in order to catch the ball at a height of 1.3m above the ground. (Use g = 9.8)


Thanks in advance :)

  • math -

    At the maximum height of 4.9m, the ball has risen for 1 sec. (That's the amount of time it takes to fall from 1m height to 0.)

    So, v = 9.8-9.8t
    h = -4.9t^2 + 9.8t since h(0) = 0
    at t=1.857 sec, h = 1.3, x=52 m

    So, the fielder must run 65-52 = 13m in 1.857sec, or 7m/s

    (assuming he doesn't extend his arm too far to grab the ball!)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Dan

    Darryl Strawberry hits a baseball with a horizontal velocity of 45 m/s and a vertical velocity of 25 m/s... Find the time it takes for the ball to travel to the highest point Find the total time the ball is in flight Find the range …
  2. Projective Motion Problem

    Darryl Strawberry hits a baseball with a horizontal velocity of 45 m/s and a vertical velocity of 25 m/s... Find the time it takes for the ball to travel to the highest point Find the total time the ball is in flight Find the range …
  3. calculus

    If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 64 ft/sec, its height after t seconds is s(t)=64+64t–16t2 . What is the maximum height the ball reaches?
  4. Calculus

    If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t)=32+112t–16t2 . What is the maximum height the ball reaches?
  5. math

    If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t)=32+80t–16t2. What is the maximum height the ball reaches?
  6. calculas

    If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 80 ft/sec, its height after t seconds is s(t)=48+80t–16t2. What is the maximum height the ball reaches?
  7. Physics

    2. A golf ball is hit off the tee with an initial speed of 32 m/s at an angle of 29° with respect to the horizontal. a. What is the maximum height the ball reaches?
  8. Math

    A batsman hits a cricket ball 'off his toes' towards a fieldsman who is 65 m away. The ball reaches a maximum height of 4.9 m and the horizontal compoenent of its velocity is 28 m/s. Find the constant speed with which the fieldsman …
  9. Physics

    A ball is shot from the ground into the air. At a height of 9.1 m, the velocity is observed to be v = (6.6 + 5.7 ) m/s, with horizontal and upward. (a) To what maximum height does the ball rise?
  10. College Calculus

    If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 96 ft/sec, its height after t seconds is s(t)=48+96t−16t^2. What is the maximum height the ball reaches?

More Similar Questions