college algebra

posted by .

write the equation of the hyperbola in standard form:

x^2-4x-y^2+6y=9

  • analytic geometry -

    (x-2)^2 -(y-3)^2 = 9 +4 -9 = 4

    [(x-2)/2]^2 - [(y-3)/2]^2 = 1

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. College Algebra.

    Find the equation in standard form of the hyperbola that satisfies the stated condition. Foci (0,5) and (0,-5), asymptotes y = x and y =-x
  2. college algebra

    Use point-slope form to write the equation of the line with the given properties. Write the equation in standard form. m is undefined passing through P(-7, -7)
  3. College algebra

    Write the equation of m=6/7 through (0,3) in standard form
  4. algebra 2

    Write an equation in standard form for the hyperbola with center (0,0), vertex(4,0) , and focus (8,0).
  5. algebra 2

    Write an equation in standard form for the hyperbola with center (0,0), vertex(4,0) , and focus (8,0). 1) x^2/64-x^2/16=1 2)x^2/16-y^2/64=1 3)y^2/48-x^2/16=1 4)x^2/16-y^2/48=1
  6. College algebra

    Find the standard form of the equation of the hyperbola with the given characteristics. Foci:(+4,0) or (-4,0) Asymptotes: y=4x or y=-4x.
  7. math30

    The equation of the hyperbola is (x-3)^2/4 - (y+1)^2/16 =-1. What is the range?
  8. college algebra--need help please!!

    write the standard form of the equation and the general form of the equation of the circle with radius r and center (h,k) r=10; (h,k)=(8,-6)
  9. algebra

    a hyperbola has vertices (+-5,0) and one focus (6,0) what is the standard form equation of the hyperbola.
  10. algebra

    Can someone please help... a hyperbola has vertices (+-5,0) and one focus (6,0) what is the standard form equation of the hyperbola.

More Similar Questions