posted by Anonymous .
A 0.115-L sample of an unknown HNO3 solution required 31.1 mL of 0.100 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?
2HNO3 + Ba(OH)2 ==> Ba(NO3)2 + 2H2O
mols Ba(OH)2 = M x L = ?
convert mols Ba(OH)2 to mols HNO3 using the coefficients in the balanced equation. That is mols HNO3 = 2*mols Ba(OH)2
Then M HNO3 = mols HNO3/L HNO3.
Thank you very much Dr. Bob for your help. I didn't post the original question, but was working on a similar problem. It probably would have taken me an hour to figure this out without your help. Thanks again!