Calculus
posted by Brock .
Complete the square to write the equation x^2 + y^2  6x  2y + 4 = 0 in standard form. Use the standard form of the equation to identify the center and the radius of the circle.

x^2 + y^2  6x  2y + 4 = 0
x^2  6x + 9 + y^2  2y + 1 = 4 + 9 + 1
(x3)^2 + (y1)^2 = 6
I will leave it up to you to take it from there.