posted by Brock
Complete the square to write the equation x^2 + y^2 - 6x - 2y + 4 = 0 in standard form. Use the standard form of the equation to identify the center and the radius of the circle.
x^2 + y^2 - 6x - 2y + 4 = 0
x^2 - 6x + 9 + y^2 - 2y + 1 = -4 + 9 + 1
(x-3)^2 + (y-1)^2 = 6
I will leave it up to you to take it from there.