# Calculus

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Find if the limit exists.
lim tan(x)/x
x->0
Please show how you determined this.
Thanks!

• Calculus -

series for tan x = x + x^3/3 + 2x^5/15 ...
divide by x
1 + x^2/3 + 2 x^5/15 ....
for x = 0 we get 1

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