If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the nearest watt?
3dB corresponds to a factor of 2. So, 3W
To calculate the output power of the electronic circuit, we need to understand that a loss of 3 decibels means that the power is reduced to half (0.5) of the original power.
To find the output power, multiply the input power by the ratio of the power converted in decibels to the original power:
Output Power = Input Power × 10^(Loss in dB / 10)
In this case, the input power is 6 watts, and the loss is 3 decibels.
Output Power = 6 watts × 10^(-3 dB / 10)
Calculating the expression inside the parentheses:
Output Power = 6 watts × 10^(-0.3)
Converting the exponent:
Output Power = 6 watts × 0.501187
Rounding to the nearest watt:
Output Power ≈ 3 watts
Therefore, the output power of the electronic circuit would be approximately 3 watts.
To determine the output power of the electronic circuit, we need to understand the concept of decibels and how they relate to power.
Decibels (dB) measure the relative difference between two power levels. In this case, a loss of 3 dB means there is a decrease in power. The formula to convert between decibels and power is:
P2 = P1 * 10^(dB/10),
where P1 is the initial power level, P2 is the final power level, and dB is the change in decibels.
To solve for the output power (P2) in this scenario, we can use the given information:
P1 = 6 watts (input power),
dB = -3 dB (loss of 3 decibels).
Substituting these values into the formula:
P2 = 6 * 10^(-3/10).
Now we can calculate the output power:
P2 ≈ 6 * 10^(-0.3) ≈ 6 * 0.501187 ≈ 3.007122.
Rounding the output power to the nearest watt, we get:
Output power ≈ 3 watts.