physics

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A .035-kg bullet is fired vertically at 180 m/s into a .15-kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collicion, assuming the bullet embeds itself in the ball? Answer in meters.

  • physics -

    initial momentum = .035*180 = 6.3 kg m/s
    new mass = .035+.15 = .185 kg
    new momentum = old momentum
    6.3 = .185 v
    v = 34.05 m/s
    Ke = (1/2) m v^2 = (1/2)(.185)(34.05)^2
    = 107.3 Joules
    m g h = 107.3
    h = 59.1

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