geometry
posted by angela .
FIND THE PERIMETER AND AREA OF A RIGHT IF THE SHORTEST SIDE IS 20MM. AND THE LONGEST SIDE IS 52MM. INCLUDE CORRECT UNITS WITH EACH PART OF YOUR SOLUTION.

Is this a right TRIANGLE?
If it is, I'll be glad to help you. 
YES

First, we need to determine the length of the third side by using the Pythagorean Theorem.
a^2 + b^2 = c^2
20^2 + b^2 = 52^2
400 + b^2 = 2704
b^2 = 2304
b = 48
The perimeter is the sum of the three sides.
20 + 48 + 52 = P
The area is found by using this formula:
A = 1/2 * b * h
A = (1/2) * 20 * 48
A = ________sq. mm.