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When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed. how many moles of SO2 and O2 did not enter into combination?

  • Chemistry -

    2SO2 + O2 ==> 2SO3

    The long way of solving but easiest to explain is this.
    Convert 10 mols SO2 to mols SO3.
    10 x (2 mols SO3/2 mols SO2) = 10

    Convert 15 mols O2 to mols SO3.
    15 x (2 mols SO3/1 mol O2) = 30 mols SO3.

    So we know 10 mols SO3 is the limiting reagent. How much O2 will that use?
    10 mols SO3 x (1 mol O2/2 moles SO3) = 5 mols O2. So we use all of the SO3(leaving zero not reacted), we use 5 of the 15 (leaving 10) moles O2 not reacted.

  • Football -

    just use formula idiot

  • Chemistry -

    So2=2 .O2=11

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