Chemistry
posted by Christinaa .
Calculate the pressure, in atmospheres, of 2.80 moles helium gas in a 18.0 liters container at 24 degrees celcius.

The ideal gas law is PV = nRT. You have n (2.80mol), V (18L), and T (24°C). R is the universal gas constant (which equals 0.0821 L* atm/mol * K).
Convert Celsius to Kelvin:
24°C + 273K = 297K
insert the numbers into the equation:
P(18L) = (2.80mol)(0.0821 L atm/mol * K)(297K)
isolate P:
P = (2.80mol)(0.0821 L atm/mol * K)(297K)/(18L)
P = 0.178 atm