chemistry

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Nitrogen-13 has a half-life of 10 minutes. Given a starting mass of 2.00 g of nitrogen-13, how many grams will remain at the end of 30 minutes?

  • chemistry -

    k = 0.693/t1/2
    ln(No/N) = kt
    No = 2.00
    N = unknown
    k from above
    t = 30 min
    Solve for N.

    You can also use this.
    30 min is obviously 3 half lives; therefore, 23 = 8 and 2.00 x (1/8) = ?

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