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A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s2 until it stops. What distance does the train travel while slowing down?

  • Physics -

    v^2 = u^2 - 2*a*s
    here, v = 0 (final speed)
    u = 24 m/s
    a = 0.065 m/s^2
    Solve above to obtain s - distance covered while slowing down.

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