Calculus - please check my work
posted by Henry .
Differentiate each function
a) y = -3x^2 + 5x - 4
b) f(x) = 6/x - 3/(x^2)
c) f(x) = (3x^2 - 4x)(x^3 + 1)
the answers i got for each was:
a) y'= -6x + 5
b) f'(x)= -6/x^2 + 6/x^3
c) f'(x)= 15x^4 + 6x - 16x^3 - 4
please double check and let me know if these are correct, thank you.
All correct, well done!
thank you! can u help me on this question please
determine the coordinates of two points on the plane with equation 5x + 4y - 3z = 6
Any point on the plane will satisfy the equation.
Since there are three variables x,y and z, you can fix any two variables and solve for the third.
Assuming arbitrarily y=6, z=6
So (0,6,6) is a point on the plane.