Calculus - please check my work

posted by Henry

Differentiate each function

a) y = -3x^2 + 5x - 4

b) f(x) = 6/x - 3/(x^2)

c) f(x) = (3x^2 - 4x)(x^3 + 1)

the answers i got for each was:

a) y'= -6x + 5

b) f'(x)= -6/x^2 + 6/x^3

c) f'(x)= 15x^4 + 6x - 16x^3 - 4

please double check and let me know if these are correct, thank you.

  1. MathMate

    All correct, well done!

  2. Henry

    thank you! can u help me on this question please

    determine the coordinates of two points on the plane with equation 5x + 4y - 3z = 6

  3. MathMate

    Any point on the plane will satisfy the equation.

    Since there are three variables x,y and z, you can fix any two variables and solve for the third.

    Assuming arbitrarily y=6, z=6
    So (0,6,6) is a point on the plane.

  4. Henry

    thank you

  5. MathMate

    You're welcome!

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