math
posted by Leo .
A car has a 12 volt battery. The engine has a resistance of 0.22 ohms. How many amps will be drawn from the battery when the key is turned?

V=IR
V= 12v
R= 0.22 ohms
I = V/R
= 12/0.22
=54.5 amps 
E= I x R is the formula
the answer is .5454
I=amperes
R=ohms
E=volts
12volts/22 
actually David is right. I forgot the decimal place from the 22 so it is 54.5 amps

thank you

Three cells are connected. The external resistance of each cell is 2 ohms. The voltage of each cell is 1.5 volts. The resistance of the external circuit is 2.3 ohms. What is the circuit current to the nearest tenth ampere?
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