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Physics help!!!

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What potential difference is required in an electron microscope to give electrons a wavelength of 0.05 nm ?

  • Physics help!!! -

    For that de Broglie wavelength, Electron momentum = p = h/(5*10^-11 m)
    where h is Planck's constant.

    Momentum p = 6.62*10^-34/5*10^-11
    = 1.32*10^-23 kg*m/s

    Energy = p^2/(2m) = e*V
    m = electron mass
    e = electron charge
    Solve for potential difference, V.

    V = p^2/(2*m*e)

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