Post a New Question

PHYSICS

posted by .

Driving in your car with a constant speed of v = 11.7 m/s, you encounter a bump in the road that has a circular cross section, as indicated in the figure below. If the radius of curvature of the bump is r = 34.4 m, calculate the apparent weight of a 65.9 kg person in your car as you pass over the top of the bump.
I honestly don't even know where to start with this question. I am having a very hard time with apparent weight in general so please don't criticize me. Thank you for any and all help!

  • PHYSICS -

    Assume that car tires and shock absorbers do not "cushion" the bump, so that the passenger's center of mass follows the profile of the bump.

    The apparent weight is the force that the seat applies to the person to keep him or her in place. At the top of the bump, less force is required because there is a downward centripetal acceleration.

    The person's actual weight is M g = 645.8 N

    That gets reduced by
    M V^2/R = 262.2 N
    temporarily, due to the bump

    The apparent weight is then 383.6 N

  • PHYSICS -

    The centripetal acceleration is down, toward the center of the circle
    Ac = v^2/R = 11.7^2/34.4 = 3.98 m/s^2

    The gravity force down on driver = m g = 65.9*9.8 = 646 Newtons

    The force up on the driver from the car is F, the weight a scale would measure if placed on the seat.
    so
    total force down on driver = m (Ac)
    646 - F = 65.9 (3.98)
    F = 646 - 262
    F = 384 Newtons

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    Driving in your car with a constant speed of v=13.0 m/s, you encounter a bump in the road that has a circular cross section. If the radius of curvature of the bump is r=33.2 m, calculate the force the car sear exerts on a 72.7 kg person …
  2. physics

    Driving in your car with a constant speed of 12 m/s, you encounter a bump in the road that has a circular cross section. If the radius of curvature of the bump is r = 34 m, find the apparent weight of a 60 kg person in your car as …
  3. Physics

    Driving in your car with a constant speed of 12 m s you encounter a bump in the road that has a circular cross-section. The radius of curvature of the bump is 35.2 m. At what speed must you go over the bump if people in your car are …
  4. physics

    Driving in your car with a constant speed of 12 m/s, you encounter a bump in the road that has a circular cross-section. If the radius of curvature of the bump is 35 m, find the apparent weight of a 63-kg person in your car as you …
  5. Physics

    Driving in your car with a constant speed of 12 , you encounter a bump in the road that has a circular cross-section, as indicated in the figure . If the radius of curvature of the bump is 35 , find the apparent weight of a 70- person …
  6. physics

    driving in a car with constant speed of 12m/s,then encounter to a bump that has a circular cross-section and a radius of 35m.find the apparent weight of a 70 kg person in the car over the top of bump
  7. physics

    You are driving your car over a circular-shaped bump in the road that has a radius of curvature of 75.9 m. A)If the car is traveling at a constant speed of 18.3 m/s, calculate the apparent weight of your 56.1 kg passenger as you pass …
  8. physics

    Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure. If the radius of curvature of the bump is 52 m, find the apparent weight of a 66-kg …
  9. physics help

    Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure. If the radius of curvature of the bump is 52 m, find the apparent weight of a 66-kg …
  10. physics

    Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure (Figure 1) . Part A If the radius of curvature of the bump is 52 m, find the apparent …

More Similar Questions

Post a New Question