algebra
posted by lucia .
The sum of two number is 40.Two times the smaller number exceeds the larger number by 38.Find the number

let the smaller be x
then the larger is 40x
"Two times the smaller number exceeds the larger number by 38"
> 2x > (40x) by 38
2x = 40x + 38
3x = 78
x = 26
the smaller is 26
the larger is 14
contradiction!
Your wording should have been
"Two times the larger number exceedss the smaller number by 38
then
2(40x)  x = 38
80  2xx = 38
3x = 42
x = 14
the smaller is 14, the larger is 26
check:
2(26) = 52
does 52 exceed 14 by 38 ? YES
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