statistics
posted by smrey .
A CBS/New York Times poll found that 350 out of 757 adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 95% confidence level.

Example of a proportional confidence interval formula:
CI95 = p ± (1.96)[√(pq/n)]
...where p = x/n, q = 1  p, and n = sample size.
Note: ± 1.96 represents 95% confidence interval.
For p in your problem: 350/757 = .46
For q: 1  p = 1  .46 = .54
n = 757
I let you take it from here to calculate the interval.
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