Update Math Question
posted by jessica .
The area of triangle B is 64 times greater than the area of triangle A.The perimeter of triangle B is how many times greater than the perimeter of triangle A?
how many times greater than the perimeter of triangle A?
A. 8 times greater
B.64 times greater
C.128 times greater
D.256 times greater

area=sqrt(s(sa)(sb)(sc)) where s is the semi perimeter.
so area=f(sqrt s^4) or f(s^2)
so if area increases by 64, s must have increased by 8 
128
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