Algebra II
posted by Greg B. .
Solve 4^(x+2)= 160
How would I round this answer to the nearest hundredth?
My answer was 200, I don't believe I worked the problem out correctly.

4^(x+2)=160
(x+2)ln4 = ln160
x+2 = ln160/ln4
x = ln160/ln4  2
= 1.66
Did you think to check whether 4^202 = 160? I mean, 4^4 = 256!
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