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chemistry

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The first-order rate constant for photodissociation of A is 5.97 1/h. Calculate the time needed for the concentration of A to decrease to the following quantities.

a. 5% of its original value h

b. one-third of its initial concentration h

  • chemistry -

    k = 5.97 WHAT.
    ln(No/N) = kt
    ln(100/5) = 5.97*t
    Solve for t.
    I don't know the units (seconds, min, hours, days, years) because I can't tell from your value of 5.97 1/h.

  • chemistry -

    5.97 1/hour

  • chemistry -

    Then the time is in hours.
    b is worked the same way.

  • chemistry -

    could yo explain part b?

  • chemistry -

    Same equation.
    You can make up any number you want for No, then N is 1/3 that. I would pick a convenient number for No such as 300, then N = 100, and solve for t.
    No could be 1 and N = 1/3 etc.

  • chemistry -

    Thank You Very !

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